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P2: Electricity

P2.1 Mains Electricity – AC Current and VoltageP2.2 Power, Current, and VoltageP2.3 Ohm's Law and ResistanceP2.4 Circuits – Series and Parallel
P2: Electricity

Power, Current, and Voltage

Understanding electrical quantities and calculating power in circuits

Electrical circuit components

Electrical Power

The rate of energy transfer in circuits

Current, Voltage, and Resistance
The fundamental electrical quantities

Current (I) is the rate of flow of electric charge. It's measured in Amperes (A) and calculated using I = Q/t (charge divided by time). One ampere equals one coulomb of charge flowing per second.

Voltage (V), also called potential difference, is the energy transferred per unit charge. It's measured in Volts (V). One volt equals one joule per coulomb (J/C).

Resistance (R) is the opposition to current flow in a circuit. It's measured in Ohms (Ω) and causes a voltage drop across components.

Power Equations
Three ways to calculate electrical power

Power (P) is the rate of energy transfer, measured in Watts (W). There are three equivalent formulas:

P = V × I

Voltage × Current

P = I² × R

Current² × Resistance

P = V² / R

Voltage² ÷ Resistance

Use the formula that matches the values you're given. All three give the same result when applied correctly.

Energy and Efficiency
Calculating energy used and device efficiency

Energy (E) is power multiplied by time: E = P × t = V × I × t. Energy is measured in Joules (J) or kilowatt-hours (kWh) for electricity billing.

Efficiency measures how much input energy becomes useful output:

Efficiency = (Useful Output ÷ Total Input) × 100%

No device is 100% efficient—some energy is always "wasted" as heat, sound, or light.

Power and Energy Calculator
Calculate electrical power using different formulas

P = V × I

Power

2300.0 W

2.300 kW

Efficiency Calculator

Efficiency = (Useful Output / Total Input) × 100%

Efficiency

75.0%

Wasted: 25.0 W

Key Terms Flashcards
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Current (I)

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Worked Example
Calculating current from power rating

Question:

A hairdryer has a power rating of 1800 W and operates at 230 V mains voltage. Calculate the current drawn and suggest an appropriate fuse.

Answer:

Using P = V × I, rearrange to find I:
I = P ÷ V = 1800 W ÷ 230 V = 7.83 A

The fuse should be rated just above normal current.
A 13 A fuse would be appropriate (next standard size above 7.83 A).

Test Your Knowledge
Question 1 of 6

What is the formula for electrical power?